[FLASH-USERS] adiabatic simulation

Eddie Hansen ehansen at flash.uchicago.edu
Fri Nov 15 17:04:12 EST 2019


It depends on other physics you may have turned on. We can write a
simplistic  energy equation as:

d(energy)/dt + grad(energy_flux) = -L

where L is the cooling/heating source term. FLASH will solve the equation
without any cooling/heating (L=0), which would potentially make the system
adiabatic. But there's other physics that can appear on the right hand side
of the equation. And you might also consider the system to not be adiabatic
depending on the boundary conditions being used.

On Fri, Nov 15, 2019 at 3:35 PM guido <g.granda at irya.unam.mx> wrote:

> Hello Flash users,
>
> I'm wondering what FLash does when a simulation is configured without
> the cooling module. Does flash solve the energy equation without the
> cooling and heating terms? Do you know if using such a configuration
>
> plus an equation of state with gamma=5/3 is equivalent to a adiabatic
> simulation ?
>
> Cheers,
>
>

-- 
Eddie Hansen, PhD
Postdoctoral Scholar
University of Chicago
607-341-6126 | Flash Center
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