<div dir="ltr"><div>Nitish,</div><div><br></div><div>To add another possibility to Sijoy's, please look in the latest FLASH4 user manual and ensure you are interpreting the "depo" variable correctly -- the laser package does not always use the same units as the rest of the simulation.</div><div><br></div><div>Scott<br></div></div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">On Sat, Mar 9, 2019 at 10:14 PM Sijoy C D <<a href="mailto:cjoycd@gmail.com">cjoycd@gmail.com</a>> wrote:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex"><div dir="auto">Hi,<div dir="auto"><br><div dir="auto">If your computational domain is set with free outflow conditions the materials leave the domain carrying internal energy and kinetic energy (outflow BC). In the laser slab problem setup, it might be possible the background material and at later stages the targets material may flow out the computational domain. </div><div dir="auto">This is only one possibility .<br></div></div></div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">On Sun, Mar 10, 2019, 10:38 AM Acharya, Nitish <<a href="mailto:nachary2@ur.rochester.edu" target="_blank">nachary2@ur.rochester.edu</a>> wrote:<br></div><blockquote class="gmail_quote" style="margin:0px 0px 0px 0.8ex;border-left:1px solid rgb(204,204,204);padding-left:1ex">
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<p style="margin-top:0px;margin-bottom:0px">Thanks Klaus. </p>
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<p style="margin-top:0px;margin-bottom:0px">Yes, indeed the "energies" in both of the sources have units of energy. Thanks so much for clarifying about it. Right now, I'm having an issue regarding laser energy deposition. How does it compare to total energy? From
what I understand, any increase in total energy at any instant should equal total energy deposition until that time. However, I am getting Laser Energy Deposition higher than the total energy at almost all the time instants. Do you have any idea what's going
on?</p>
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<p style="margin-top:0px;margin-bottom:0px">Thanks,</p>
<p style="margin-top:0px;margin-bottom:0px">Nitish</p>
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<div id="gmail-m_4476746312386492597m_5050135955051820582divRplyFwdMsg" dir="ltr"><font style="font-size:11pt" face="Calibri, sans-serif" color="#000000"><b>From:</b> Klaus Weide <<a href="mailto:klaus@flash.uchicago.edu" rel="noreferrer" target="_blank">klaus@flash.uchicago.edu</a>><br>
<b>Sent:</b> Tuesday, March 5, 2019 6:23:05 PM<br>
<b>To:</b> Acharya, Nitish<br>
<b>Cc:</b> Scott Feister; <a href="mailto:flash-users@flash.uchicago.edu" rel="noreferrer" target="_blank">flash-users@flash.uchicago.edu</a><br>
<b>Subject:</b> Re: [FLASH-USERS] Total energy and Laser Deposition</font>
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<div class="gmail-m_4476746312386492597m_5050135955051820582PlainText">On Tue, 5 Mar 2019, Acharya, Nitish wrote:<br>
<br>
> Thanks Scott. I thought it was ergs/g as the energies in FLASH <br>
> calculated seemed to be all specific energies. So, I did multiply the <br>
> energies by mass. Also, since it was a 2D domain, multiplication by mass <br>
> was infact mass per length. This is what I did. And I was wondering what <br>
> length parameter should I use to get the total energy.<br>
<br>
The integral quantities written to the flash.dat (or similar) file should <br>
have totals of *energy* in the appropriate columns, at least in 3D <br>
and in lower-D geometries when the "omitted directions" are angles not <br>
lengths. So for 2D cylindrical geometry, they are energies (integration<br>
over a full 2\pi range of azimuthal angle is implied).<br>
<br>
The "power" specified for the Laser energy deposition should indeed be<br>
a power (energy / time) also in the 2D cylindrical case, at least if<br>
ed_laser3Din2D is used (not sure about when ed_laser3Din2D is false).<br>
The "energies" in lasslab_LaserEnergyProfile.dat should then indeed<br>
have units of energy, not energy per length.<br>
<br>
You should NOT have to multiply by mass if you compare energies from<br>
those two sources (flash.dat and _LaserEnergyProfile.dat files).<br>
And I believe you should not have to multiply (or divide) by a length <br>
either, under the mentioned conditions.<br>
<br>
Klaus<br>
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