<meta http-equiv="Content-Type" content="text/html; charset=utf-8"><div dir="auto">Not sure what else you have going on in your simulation, but why not rotate your frame of reference? The 1 beam coming in at 45 degrees is still just 1 beam pointed towards the center of a sphere. You could have it come from 0 deg (the equator), and then it will look symmetric.</div><br><div class="gmail_quote"><div dir="ltr" class="gmail_attr">On Thu, Sep 10, 2020, 2:55 AM 方可 <<a href="mailto:kfang@iphy.ac.cn">kfang@iphy.ac.cn</a>> wrote:<br></div><blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex"><p>
<span style="font-family:Verdana;font-size:14px">Hi Shu:</span>
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<span style="font-family:Verdana;font-size:14px">Thank you for your explanation, this make sense and now i understand why at the pole end the intensity is always stronger. I will try some other methods like 3D simulation. </span>
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<span style="font-family:Verdana;font-size:14px">Best regards,</span>
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<span style="font-family:Verdana;font-size:14px">-Ke Fang</span>
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-----原始邮件-----<br>
<b>发件人:</b><span id="m_5853046075679043878rc_from">"Shu Zhang" <<a href="mailto:shz133@eng.ucsd.edu" target="_blank" rel="noreferrer">shz133@eng.ucsd.edu</a>></span><br>
<b>发送时间:</b><span id="m_5853046075679043878rc_senttime">2020-09-10 12:34:17 (星期四)</span><br>
<b>收件人:</b> "方可" <<a href="mailto:kfang@iphy.ac.cn" target="_blank" rel="noreferrer">kfang@iphy.ac.cn</a>><br>
<b>抄送:</b> "<a href="mailto:flash-users@flash.uchicago.edu" target="_blank" rel="noreferrer">flash-users@flash.uchicago.edu</a>" <<a href="mailto:flash-users@flash.uchicago.edu" target="_blank" rel="noreferrer">flash-users@flash.uchicago.edu</a>><br>
<b>主题:</b> Re: [FLASH-USERS] laser setup in cylindrical geometry<br>
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Hi Ke,
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After 3D-in-2D projection, the simulation is working like you have a ring of lasers injected at 45 deg. So at the pole, you have higher overlapped intensity, but at the equator, the averaged intensity is lower. This is real<span style="color:#000000"> when multiple large spot beams are injected at 45 deg. </span><br>
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-Shu
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On Sep 9, 2020, at 8:32 PM, 方可 <<a href="mailto:kfang@iphy.ac.cn" target="_blank" rel="noreferrer">kfang@iphy.ac.cn</a>> wrote:
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Shu:
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Thank you very much for your answer, but i think there is still some problem. What i mean is when i inject the laser with 45 deg, truly the intensity and energy is not uniform, but i think it should be symmetrically to the 45 degree injection axis.
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When i use the cartesian geometry without 3Din2D laser setup, the results is symmetrical, but I need run this in cylindrical geometry. I added 2 screenshot of these results of pressure distribution in the mail attachment.
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Thank you for your help!
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-Ke Fang
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-----原始邮件-----<br>
<b>发件人:</b><span id="m_5853046075679043878rc_from">"Shu Zhang" <<a href="mailto:shuzhang@princeton.edu" target="_blank" rel="noreferrer">shuzhang@princeton.edu</a>></span><br>
<b>发送时间:</b><span id="m_5853046075679043878rc_senttime">2020-09-10 10:56:45 (星期四)</span><br>
<b>收件人:</b> "方可" <<a href="mailto:kfang@iphy.ac.cn" target="_blank" rel="noreferrer">kfang@iphy.ac.cn</a>><br>
<b>抄送:</b> "<a href="mailto:flash-users@flash.uchicago.edu" target="_blank" rel="noreferrer">flash-users@flash.uchicago.edu</a>" <<a href="mailto:flash-users@flash.uchicago.edu" target="_blank" rel="noreferrer">flash-users@flash.uchicago.edu</a>><br>
<b>主题:</b> Re: [FLASH-USERS] laser setup in cylindrical geometry<br>
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Hi Ke,
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Your settings are correct. The 3D in 2D laser ray tracing is calculating the laser ray deflection and the energy deposition in 3D and then project the energy deposition on the 2D RZ coordinates. Thus, when the laser is injected in 45 deg, naturally
the projected energy deposition is not really uniform. It would look like uniform if you have a planar target normal to the Z(Y) axis.
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-Shu
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On Sep 9, 2020, at 7:42 PM, 方可 <<a href="mailto:kfang@iphy.ac.cn" target="_blank" rel="noreferrer">kfang@iphy.ac.cn</a>> wrote:
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Hi, everyone:
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My simulation is using one laser beam irradiate on a spherical shell, and this laser beam have a 45 degree angle to x-axis. I used the cylindrical geometry, and from the output hdf5 files, I found that the intensity of laser is not symmetrically on the surface
of the shell. But when i used the cartesian geometry with same 45 degree incident laser, the intensity on the shell is uniform and symmetrically.
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I guess here are some problems when i'm seting up the laser beam. My laser setup in the .par file is as follows:
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useEnergyDeposition = .true.
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ed_maxRayCount = 20000
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ed_gradOrder = 2
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# Activate 3D-in-2D ray trace:
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ed_laser3Din2D = .true.
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ed_laser3Din2DwedgeAngle = 0.1
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### LASER IO OPTIONS ###
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ed_useLaserIO = .true.
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ed_laserIOMaxNumberOfPositions = 10000
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ed_laserIOMaxNumberOfRays = 128
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### SETUP LASER PULSES ###
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ed_numberOfPulses = 1<span style="white-space:pre-wrap"> </span>
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# Define Pulse 1:
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ed_numberOfSections_1 = 4<span style="white-space:pre-wrap"> </span>
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ed_time_1_1 = 0.0
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ed_time_1_2 = 0.01e-09
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ed_time_1_3 = 0.50e-09
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ed_time_1_4 = 0.51e-09
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ed_power_1_1 = 0.0
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ed_power_1_2 = 1.52e+012
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ed_power_1_3 = 1.52e+012
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ed_power_1_4 = 0.0
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### SETUP LASER BEAM ###
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ed_numberOfBeams = 1
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# Setup Gaussian Beam:
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ed_lensX_1 = 10.0<span style="white-space:pre-wrap"> </span>
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ed_lensZ_1 = 10.0
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ed_lensY_1 = 0.0
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ed_lensSemiAxisMajor_1 = 3.0e-01
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ed_targetX_1 = 212.0e-04
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ed_targetZ_1 = 212.0e-04
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ed_targetY_1 = 0.0
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ed_targetSemiAxisMajor_1 = 225.0e-04
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ed_targetSemiAxisMinor_1 = 225.0e-04
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ed_pulseNumber_1 = 1
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ed_wavelength_1 = 0.351
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ed_crossSectionFunctionType_1 = "gaussian2D"
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ed_gaussianExponent_1 = 4.0
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ed_gaussianRadiusMajor_1 = 212e-04
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ed_gaussianRadiusMinor_1 = 212e-04
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ed_numberOfRays_1 = 4096
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ed_gridType_1 = "radial2D"
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ed_gridnRadialTics_1 = 64
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ed_semiAxisMajorTorsionAngle_1= 0.0
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ed_semiAxisMajorTorsionAxis_1 = "x"
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And in mesh parameters:
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geometry = "cylindrical"<span style="white-space:pre-wrap"> </span>
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And, this shell is a hollow spherical shell with outer radius 300 microns and inner radius 150 microns.
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So, what should i do to let the intensity of the laser on the shell to be symmetrically to the 45 degree incident axis?
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Thank you for your attention and help !
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Best regards,
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<span style="font-size:small">Ke Fang</span>
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<span style="line-height:22.1px;font-size:x-small">phd student</span>
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<span style="line-height:22.1px;font-size:x-small">Chinese Academy of Sciences</span>
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<span id="m_5853046075679043878cid:0881EF10-9C37-4011-8F1A-5FE879142424"><45degree_cartesian.PNG></span><span id="m_5853046075679043878cid:20BB5A07-7D96-4795-97B4-255083219973"><45degree_cylindrical.PNG></span>
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